2006. 9. 20. 19:19
옛날카테고리/함장(?)일지
류광님의 포스팅에서 보았던 inureyes님이 만드신 LaTeX 플러그인을 설치했다.
약간의 삽질이 있었지만, 해보니 잘 되는군..
[tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex] [tex]\Large f(x)=\int_{-\infty}^x e^{-t^2}dt[/tex] [tex]\LARGE f=b_o+\frac{a_1}{b_1+\frac{a_2}{b_2+\frac{a_3}{b_3+a_4}}}[/tex]
[tex]\Large\overbrace{a,...,a}^{\text{k a^,s}},\underbrace{b,...,b}_{\text{lb^,s}}\hspace{10}\large\underbrace{\overbrace{a...a}^{\text{ka^,s}},\overbrace{b...b}^{\text{l b^,s}}}_{\text{k+l elements}}[/tex] [tex]\Large A\ =\\large\left(\begin{array}{c.ccc}&1&2&3\\\hdash1&a_{11}&a_{12}&a_{13}\\2&a_{21}&a_{22}&a_{23}\\3&a_{31}&a_{32}&a_{33}\end{array}\right)[/tex]
[tex]\Large\left.\begin{eqnarray}x+y+z&=&3\\2y&=&x+z\\2x+y&=&z\end{eqnarray}\right\}[/tex] [tex]\Large\hspace{5}\unitlength{1}\picture(175,100){~(50,50){\circle(100)}(1,50){\overbrace{\line(46)}^{4$\;\;a}}(52,50){\line(125)}~(50,52;115;2){\mid}~(52,55){\longleftar[60]}(130,56){\longrightar[35]}~(116,58){r}~(c85,50;80;2){\bullet}(c85,36){3$-q}~(c165,36){3$q}(42,29){\underbrace{\line(32)}_{1$a^2/r\;\;\;}}~}[/tex]
약간의 삽질이 있었지만, 해보니 잘 되는군..
[tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex] [tex]\Large f(x)=\int_{-\infty}^x e^{-t^2}dt[/tex] [tex]\LARGE f=b_o+\frac{a_1}{b_1+\frac{a_2}{b_2+\frac{a_3}{b_3+a_4}}}[/tex]
[tex]\Large\overbrace{a,...,a}^{\text{k a^,s}},\underbrace{b,...,b}_{\text{lb^,s}}\hspace{10}\large\underbrace{\overbrace{a...a}^{\text{ka^,s}},\overbrace{b...b}^{\text{l b^,s}}}_{\text{k+l elements}}[/tex] [tex]\Large A\ =\\large\left(\begin{array}{c.ccc}&1&2&3\\\hdash1&a_{11}&a_{12}&a_{13}\\2&a_{21}&a_{22}&a_{23}\\3&a_{31}&a_{32}&a_{33}\end{array}\right)[/tex]
[tex]\Large\left.\begin{eqnarray}x+y+z&=&3\\2y&=&x+z\\2x+y&=&z\end{eqnarray}\right\}[/tex] [tex]\Large\hspace{5}\unitlength{1}\picture(175,100){~(50,50){\circle(100)}(1,50){\overbrace{\line(46)}^{4$\;\;a}}(52,50){\line(125)}~(50,52;115;2){\mid}~(52,55){\longleftar[60]}(130,56){\longrightar[35]}~(116,58){r}~(c85,50;80;2){\bullet}(c85,36){3$-q}~(c165,36){3$q}(42,29){\underbrace{\line(32)}_{1$a^2/r\;\;\;}}~}[/tex]
